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摘要
博文主要介紹二叉樹的前/中/后/層遍歷(遞歸與棧)方法
一、前/中/后/層遍歷問題
144. 二叉樹的前序遍歷
145. 二叉樹的后序遍歷
94. 二叉樹的中序遍歷
102. 二叉樹的層序遍歷
103. 二叉樹的鋸齒形層序遍歷
二、二叉樹遍歷遞歸解析
// 前序遍歷·遞歸·LC144_二叉樹的前序遍歷
class Solution {public List<Integer> preorderTraversal(TreeNode root) {List<Integer> result = new ArrayList<Integer>();preorder(root, result);return result;}public void preorder(TreeNode root, List<Integer> result) {if (root == null) {return;}result.add(root.val);preorder(root.left, result);preorder(root.right, result);}
}// 中序遍歷·遞歸·LC94_二叉樹的中序遍歷
class Solution {public List<Integer> inorderTraversal(TreeNode root) {List<Integer> res = new ArrayList<>();inorder(root, res);return res;}void inorder(TreeNode root, List<Integer> list) {if (root == null) {return;}inorder(root.left, list);list.add(root.val); // 注意這一句inorder(root.right, list);}
}// 后序遍歷·遞歸·LC145_二叉樹的后序遍歷
class Solution {public List<Integer> postorderTraversal(TreeNode root) {List<Integer> res = new ArrayList<>();postorder(root, res);return res;}void postorder(TreeNode root, List<Integer> list) {if (root == null) {return;}postorder(root.left, list);postorder(root.right, list);list.add(root.val); // 注意這一句}
}
三、二叉樹遍歷棧解析
?
// 前序遍歷順序:中-左-右,入棧順序:中-右-左
class Solution {public List<Integer> preorderTraversal(TreeNode root) {List<Integer> result = new ArrayList<>();if (root == null){return result;}Stack<TreeNode> stack = new Stack<>();stack.push(root);while (!stack.isEmpty()){TreeNode node = stack.pop();result.add(node.val);if (node.right != null){stack.push(node.right);}if (node.left != null){stack.push(node.left);}}return result;}
}// 中序遍歷順序: 左-中-右 入棧順序: 左-右
class Solution {public List<Integer> inorderTraversal(TreeNode root) {List<Integer> result = new ArrayList<>();if (root == null){return result;}Stack<TreeNode> stack = new Stack<>();TreeNode cur = root;while (cur != null || !stack.isEmpty()){if (cur != null){stack.push(cur);cur = cur.left;}else{cur = stack.pop();result.add(cur.val);cur = cur.right;}}return result;}
}// 后序遍歷順序 左-右-中 入棧順序:中-左-右 出棧順序:中-右-左, 最后翻轉(zhuǎn)結(jié)果
class Solution {public List<Integer> postorderTraversal(TreeNode root) {List<Integer> result = new ArrayList<>();if (root == null){return result;}Stack<TreeNode> stack = new Stack<>();stack.push(root);while (!stack.isEmpty()){TreeNode node = stack.pop();result.add(node.val);if (node.left != null){stack.push(node.left);}if (node.right != null){stack.push(node.right);}}Collections.reverse(result);return result;}
}
四、二叉樹層序遍歷解析
// 102.二叉樹的層序遍歷
class Solution {public List<List<Integer>> resList = new ArrayList<List<Integer>>();public List<List<Integer>> levelOrder(TreeNode root) {//checkFun01(root,0);checkFun02(root);return resList;}public void checkFun02(TreeNode node) {if (node == null) return;Queue<TreeNode> que = new LinkedList<TreeNode>();que.offer(node);while (!que.isEmpty()) {List<Integer> itemList = new ArrayList<Integer>();int len = que.size();while (len > 0) {TreeNode tmpNode = que.poll();itemList.add(tmpNode.val);if (tmpNode.left != null) que.offer(tmpNode.left);if (tmpNode.right != null) que.offer(tmpNode.right);len--;}resList.add(itemList);}}
}
博文參考
《leetcode》